I'll try posting this here..no love in the general forum
I have a new coil to install but it may have an internal resistor (as most do now days) so I need some clarification. Underneath the old coil is a wafer shaped disc that one of the coil wires ( left side-black) runs down to. A red wire then comes off the wafer/disc and goes to the replenishment lead wire (threaded connector at the bottom of the distributor assembly). Am I correct in assuming this disc is the old resistor ? If it is, and it is now not needed, do I just cut the wafer out and just splice the wires together so now the left (as you look at it/or forward) terminal wire atop the coil is now is directly connected to the red wire ?
According to Charles Talbert (who should know ) the M-37 coil was never fitted with an external ballast resistor..ie the disc I was referring to. But the 715 was. So apparently somehow that distributor got mixed up. SO, for my purposes, I need to simply cut the disc out of the loop and splice the wires back together with the positive coil terminal being fed by #12 (the lead from the harness) and the negative going to the points/condensor.
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